6x^2+36x+8=0

Solution for 6x^2+36x+8=0 equation:

6x^2+36x+8=0

a = 6; b = 36; c = +8;
Δ = b2-4ac
Δ = 362-4·6·8
Δ = 1104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1104}=\sqrt{16*69}=\sqrt{16}*\sqrt{69}=4\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{69}}{2*6}=\frac{-36-4\sqrt{69}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{69}}{2*6}=\frac{-36+4\sqrt{69}}{12}
$